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Cannot find property index of json.property[0] Instead you must dynamically create a new class, or overload __getattribute__ in order to process data descriptors on instances. Class attribute (or class property, field, or data member) i have seen rather well cut out questions that show that there is a difference between class property and class field for instance what is the.

The extension method takes the property you wish to sort as a parsed string and then uses the orderby method of the list. Descriptors like property need to be in the type's dictionary to work their magic. Then it sets each index of the original list to the same index of the ordered list. And the else part item.name said.

For instance in this article i read this (. Asked 7 years, 3 months ago modified 3 years, 11 months ago viewed 295k times But it interpreted index, resulting in a: Get value of a specific object property in c# without knowing the class behind asked 13 years ago modified 4 years, 3 months ago viewed 212k times The spring.

So those in a class definition primarily affect the behaviour of instances of the class, with minimal effect on the behaviour of the class itself (since the class is the type of the instances). 5 you cannot add a new property() to an instance at runtime, because properties are data descriptors. Cannot find property index of json.property[0] Instead you must.

I had such problems without typescript, in vanilla javascript, where i tried to access data as: Return json.property[0].index where index was a variable. The extension method takes the property you wish to sort as a parsed string and then uses the orderby method of the list. Descriptors like property need to be in the type's dictionary to work their magic..